(t-2)(t+1)=h

Solution for (t-2)(t+1)=h equation:

Simplifying
(t + -2)(t + 1) = h

Reorder the terms:
(-2 + t)(t + 1) = h

Reorder the terms:
(-2 + t)(1 + t) = h

Multiply (-2 + t) * (1 + t)
(-2(1 + t) + t(1 + t)) = h
((1 * -2 + t * -2) + t(1 + t)) = h
((-2 + -2t) + t(1 + t)) = h
(-2 + -2t + (1 * t + t * t)) = h
(-2 + -2t + (1t + t2)) = h

Combine like terms: -2t + 1t = -1t
(-2 + -1t + t2) = h

Solving
-2 + -1t + t2 = h

Solving for variable 't'.

Reorder the terms:
-2 + -1h + -1t + t2 = h + -1h

Combine like terms: h + -1h = 0
-2 + -1h + -1t + t2 = 0

The solution to this equation could not be determined.