(t+5)(t-5)=0

Solution for (t+5)(t-5)=0 equation:

Simplifying
(t + 5)(t + -5) = 0

Reorder the terms:
(5 + t)(t + -5) = 0

Reorder the terms:
(5 + t)(-5 + t) = 0

Multiply (5 + t) * (-5 + t)
(5(-5 + t) + t(-5 + t)) = 0
((-5 * 5 + t * 5) + t(-5 + t)) = 0
((-25 + 5t) + t(-5 + t)) = 0
(-25 + 5t + (-5 * t + t * t)) = 0
(-25 + 5t + (-5t + t2)) = 0

Combine like terms: 5t + -5t = 0
(-25 + 0 + t2) = 0
(-25 + t2) = 0

Solving
-25 + t2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + t2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + t2 = 0 + 25
t2 = 0 + 25

Combine like terms: 0 + 25 = 25
t2 = 25

Simplifying
t2 = 25

Take the square root of each side:
t = {-5, 5}