(t+4)2-(t+4)-12=0

Solution for (t+4)2-(t+4)-12=0 equation:

Simplifying
(t + 4) * 2 + -1(t + 4) + -12 = 0

Reorder the terms:
(4 + t) * 2 + -1(t + 4) + -12 = 0

Reorder the terms for easier multiplication:
2(4 + t) + -1(t + 4) + -12 = 0
(4 * 2 + t * 2) + -1(t + 4) + -12 = 0
(8 + 2t) + -1(t + 4) + -12 = 0

Reorder the terms:
8 + 2t + -1(4 + t) + -12 = 0
8 + 2t + (4 * -1 + t * -1) + -12 = 0
8 + 2t + (-4 + -1t) + -12 = 0

Reorder the terms:
8 + -4 + -12 + 2t + -1t = 0

Combine like terms: 8 + -4 = 4
4 + -12 + 2t + -1t = 0

Combine like terms: 4 + -12 = -8
-8 + 2t + -1t = 0

Combine like terms: 2t + -1t = 1t
-8 + 1t = 0

Solving
-8 + 1t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1t = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1t = 0 + 8
1t = 0 + 8

Combine like terms: 0 + 8 = 8
1t = 8

Divide each side by '1'.
t = 8

Simplifying
t = 8