(t+3)+(t+4)+(t-1)=19

Solution for (t+3)+(t+4)+(t-1)=19 equation:

Simplifying
(t + 3) + (t + 4) + (t + -1) = 19

Reorder the terms:
(3 + t) + (t + 4) + (t + -1) = 19

Remove parenthesis around (3 + t)
3 + t + (t + 4) + (t + -1) = 19

Reorder the terms:
3 + t + (4 + t) + (t + -1) = 19

Remove parenthesis around (4 + t)
3 + t + 4 + t + (t + -1) = 19

Reorder the terms:
3 + t + 4 + t + (-1 + t) = 19

Remove parenthesis around (-1 + t)
3 + t + 4 + t + -1 + t = 19

Reorder the terms:
3 + 4 + -1 + t + t + t = 19

Combine like terms: 3 + 4 = 7
7 + -1 + t + t + t = 19

Combine like terms: 7 + -1 = 6
6 + t + t + t = 19

Combine like terms: t + t = 2t
6 + 2t + t = 19

Combine like terms: 2t + t = 3t
6 + 3t = 19

Solving
6 + 3t = 19

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3t = 19 + -6

Combine like terms: 6 + -6 = 0
0 + 3t = 19 + -6
3t = 19 + -6

Combine like terms: 19 + -6 = 13
3t = 13

Divide each side by '3'.
t = 4.333333333

Simplifying
t = 4.333333333