(t+3)(t-3)=40

Solution for (t+3)(t-3)=40 equation:

Simplifying
(t + 3)(t + -3) = 40

Reorder the terms:
(3 + t)(t + -3) = 40

Reorder the terms:
(3 + t)(-3 + t) = 40

Multiply (3 + t) * (-3 + t)
(3(-3 + t) + t(-3 + t)) = 40
((-3 * 3 + t * 3) + t(-3 + t)) = 40
((-9 + 3t) + t(-3 + t)) = 40
(-9 + 3t + (-3 * t + t * t)) = 40
(-9 + 3t + (-3t + t2)) = 40

Combine like terms: 3t + -3t = 0
(-9 + 0 + t2) = 40
(-9 + t2) = 40

Solving
-9 + t2 = 40

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + t2 = 40 + 9

Combine like terms: -9 + 9 = 0
0 + t2 = 40 + 9
t2 = 40 + 9

Combine like terms: 40 + 9 = 49
t2 = 49

Simplifying
t2 = 49

Take the square root of each side:
t = {-7, 7}