(t+2)2-(t+2)-12=0

Solution for (t+2)2-(t+2)-12=0 equation:

Simplifying
(t + 2) * 2 + -1(t + 2) + -12 = 0

Reorder the terms:
(2 + t) * 2 + -1(t + 2) + -12 = 0

Reorder the terms for easier multiplication:
2(2 + t) + -1(t + 2) + -12 = 0
(2 * 2 + t * 2) + -1(t + 2) + -12 = 0
(4 + 2t) + -1(t + 2) + -12 = 0

Reorder the terms:
4 + 2t + -1(2 + t) + -12 = 0
4 + 2t + (2 * -1 + t * -1) + -12 = 0
4 + 2t + (-2 + -1t) + -12 = 0

Reorder the terms:
4 + -2 + -12 + 2t + -1t = 0

Combine like terms: 4 + -2 = 2
2 + -12 + 2t + -1t = 0

Combine like terms: 2 + -12 = -10
-10 + 2t + -1t = 0

Combine like terms: 2t + -1t = 1t
-10 + 1t = 0

Solving
-10 + 1t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1t = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1t = 0 + 10
1t = 0 + 10

Combine like terms: 0 + 10 = 10
1t = 10

Divide each side by '1'.
t = 10

Simplifying
t = 10