(sin(2x))/(cos(3x))

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Solution for (sin(2x))/(cos(3x)) equation:


D( x )

cos(3*x) = 0

cos(3*x) = 0

cos(3*x) = 0

cos(3*x) = 0 <=> 3*x = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

3*x-t_1 = 0

3*x-t_1 = 0 // + t_1

3*x = t_1 // : 3

x = t_1/3

x = pi*k_1+pi/2/3 i k_1 należy do I

x in {( -oo : +oo ) / < pi*k_1+pi/2/3 : pi*k_1+pi/2/3 >} i k_1 -> {I}

sin(2*x)/cos(3*x) = 0

sin(2*x)/cos(3*x) = 0 // * cos(3*x)

sin(2*x) = 0

sin(2*x) = 0 <=> 2*x = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

2*x-t_1 = 0

2*x-t_1 = 0 // + t_1

2*x = t_1 // : 2

x = t_1/2

x = pi*k_1/2 i k_1 należy do I

x = pi*k_1/2

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