(s-d)(s+d)=

Solution for (s-d)(s+d)= equation:

Simplifying
(s + -1d)(s + d) = 0

Reorder the terms:
(-1d + s)(s + d) = 0

Reorder the terms:
(-1d + s)(d + s) = 0

Multiply (-1d + s) * (d + s)
(-1d * (d + s) + s(d + s)) = 0
((d * -1d + s * -1d) + s(d + s)) = 0

Reorder the terms:
((-1ds + -1d2) + s(d + s)) = 0
((-1ds + -1d2) + s(d + s)) = 0
(-1ds + -1d2 + (d * s + s * s)) = 0
(-1ds + -1d2 + (ds + s2)) = 0

Reorder the terms:
(-1ds + ds + -1d2 + s2) = 0

Combine like terms: -1ds + ds = 0
(0 + -1d2 + s2) = 0
(-1d2 + s2) = 0

Solving
-1d2 + s2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1s2' to each side of the equation.
-1d2 + s2 + -1s2 = 0 + -1s2

Combine like terms: s2 + -1s2 = 0
-1d2 + 0 = 0 + -1s2
-1d2 = 0 + -1s2
Remove the zero:
-1d2 = -1s2

Divide each side by '-1'.
d2 = s2

Simplifying
d2 = s2

Take the square root of each side:
d = {-1s, s}