(s-3)+s+(2s-6)=107

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Solution for (s-3)+s+(2s-6)=107 equation: 



(s-3)+s+(2s-6)=107

We move all terms to the left:

(s-3)+s+(2s-6)-(107)=0

We add all the numbers together, and all the variables

s+(s-3)+(2s-6)-107=0

We get rid of parentheses

s+s+2s-3-6-107=0

We add all the numbers together, and all the variables

4s-116=0

We move all terms containing s to the left, all other terms to the right

4s=116

s=116/4

s=29

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