(s-2)(s+2)=

Solution for (s-2)(s+2)= equation:

Simplifying
(s + -2)(s + 2) = 0

Reorder the terms:
(-2 + s)(s + 2) = 0

Reorder the terms:
(-2 + s)(2 + s) = 0

Multiply (-2 + s) * (2 + s)
(-2(2 + s) + s(2 + s)) = 0
((2 * -2 + s * -2) + s(2 + s)) = 0
((-4 + -2s) + s(2 + s)) = 0
(-4 + -2s + (2 * s + s * s)) = 0
(-4 + -2s + (2s + s2)) = 0

Combine like terms: -2s + 2s = 0
(-4 + 0 + s2) = 0
(-4 + s2) = 0

Solving
-4 + s2 = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + s2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + s2 = 0 + 4
s2 = 0 + 4

Combine like terms: 0 + 4 = 4
s2 = 4

Simplifying
s2 = 4

Take the square root of each side:
s = {-2, 2}