(s-2)(2s+1)=0

Solution for (s-2)(2s+1)=0 equation:

Simplifying
(s + -2)(2s + 1) = 0

Reorder the terms:
(-2 + s)(2s + 1) = 0

Reorder the terms:
(-2 + s)(1 + 2s) = 0

Multiply (-2 + s) * (1 + 2s)
(-2(1 + 2s) + s(1 + 2s)) = 0
((1 * -2 + 2s * -2) + s(1 + 2s)) = 0
((-2 + -4s) + s(1 + 2s)) = 0
(-2 + -4s + (1 * s + 2s * s)) = 0
(-2 + -4s + (1s + 2s2)) = 0

Combine like terms: -4s + 1s = -3s
(-2 + -3s + 2s2) = 0

Solving
-2 + -3s + 2s2 = 0

Solving for variable 's'.

Factor a trinomial.
(-1 + -2s)(2 + -1s) = 0

Subproblem 1
Set the factor '(-1 + -2s)' equal to zero and attempt to solve:

Simplifying
-1 + -2s = 0

Solving
-1 + -2s = 0

Move all terms containing s to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2s = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2s = 0 + 1
-2s = 0 + 1

Combine like terms: 0 + 1 = 1
-2s = 1

Divide each side by '-2'.
s = -0.5

Simplifying
s = -0.5
Subproblem 2
Set the factor '(2 + -1s)' equal to zero and attempt to solve:

Simplifying
2 + -1s = 0

Solving
2 + -1s = 0

Move all terms containing s to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1s = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1s = 0 + -2
-1s = 0 + -2

Combine like terms: 0 + -2 = -2
-1s = -2

Divide each side by '-1'.
s = 2

Simplifying
s = 2
Solution
s = {-0.5, 2}