(s+5.6)(s-5.6)=1

Solution for (s+5.6)(s-5.6)=1 equation:

(s+5.6)(s-5.6)=1

We move all terms to the left:

(s+5.6)(s-5.6)-(1)=0

We use the square of the difference formula

s^2-31.36-1=0

We add all the numbers together, and all the variables

s^2-32.36=0

a = 1; b = 0; c = -32.36;
Δ = b2-4ac
Δ = 02-4·1·(-32.36)
Δ = 129.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{129.44}}{2*1}=\frac{0-\sqrt{129.44}}{2}
=-\frac{\sqrt{}}{2}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{129.44}}{2*1}=\frac{0+\sqrt{129.44}}{2}
=\frac{\sqrt{}}{2}
$