(r+6/3)=(r+8/6)

Solution for (r+6/3)=(r+8/6) equation:

(r+6/3)=(r+8/6)

We move all terms to the left:

(r+6/3)-((r+8/6))=0

We add all the numbers together, and all the variables

(r+2)-((+r+8/6))=0

We get rid of parentheses

r-((+r+8/6))+2=0

We multiply all the terms by the denominator


r*6))-((+r+8+2*6))=0

We add all the numbers together, and all the variables

r*6))-((r+20))=0

We add all the numbers together, and all the variables

r*6))-((r=0

Wy multiply elements

6r^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{12}=0$