(r+2)=4(2-2r)

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Solution for (r+2)=4(2-2r) equation: 



(r+2)=4(2-2r)

We move all terms to the left:

(r+2)-(4(2-2r))=0

We add all the numbers together, and all the variables

(r+2)-(4(-2r+2))=0

We get rid of parentheses

r-(4(-2r+2))+2=0



We calculate terms in parentheses: -(4(-2r+2)), so:

4(-2r+2)

We multiply parentheses

-8r+8

Back to the equation:

-(-8r+8)



We get rid of parentheses

r+8r-8+2=0

We add all the numbers together, and all the variables

9r-6=0

We move all terms containing r to the left, all other terms to the right

9r=6

r=6/9

r=2/3

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