(q-9)-(2q+3-4q)=10q-5+q

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Solution for (q-9)-(2q+3-4q)=10q-5+q equation: 



(q-9)-(2q+3-4q)=10q-5+q

We move all terms to the left:

(q-9)-(2q+3-4q)-(10q-5+q)=0

We add all the numbers together, and all the variables

(q-9)-(-2q+3)-(11q-5)=0

We get rid of parentheses

q+2q-11q-9-3+5=0

We add all the numbers together, and all the variables

-8q-7=0

We move all terms containing q to the left, all other terms to the right

-8q=7

q=7/-8

q=-7/8

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