(q-16/q)=(36/28)

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Solution for (q-16/q)=(36/28) equation:



(q-16/q)=(36/28)
We move all terms to the left:
(q-16/q)-((36/28))=0
Domain of the equation: q)!=0
q!=0/1
q!=0
q∈R
We add all the numbers together, and all the variables
(+q-16/q)-((+36/28))=0
We get rid of parentheses
q-16/q-((+36/28))=0
We calculate fractions
q+()/28q^2+(-((+36*q)/28q^2=0
We add all the numbers together, and all the variables
q+()/28q^2+(-((+36q)/28q^2=0
We multiply all the terms by the denominator
q*28q^2+(-((+36q)+()=0
We calculate terms in parentheses: +(-((+36q)+(), so:
-((+36q)+(
Wy multiply elements
28q^3+(-((+36q)+()=0
We calculate terms in parentheses: +(-((+36q)+(), so:
-((+36q)+(
We do not support eqpression: q^3

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