(q+4=q+7+2q)

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Solution for (q+4=q+7+2q) equation: 



(q+4=q+7+2q)

We move all terms to the left:

(q+4-(q+7+2q))=0

We add all the numbers together, and all the variables

(q+4-(3q+7))=0



We calculate terms in parentheses: +(q+4-(3q+7)), so:

q+4-(3q+7)

determiningTheFunctionDomain
q-(3q+7)+4

We get rid of parentheses

q-3q-7+4

We add all the numbers together, and all the variables

-2q-3

Back to the equation:

+(-2q-3)



We get rid of parentheses

-2q-3=0

We move all terms containing q to the left, all other terms to the right

-2q=3

q=3/-2

q=-1+1/2

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