(q+11)(6q+10)=0

Solution for (q+11)(6q+10)=0 equation:

(q+11)(6q+10)=0

We multiply parentheses ..

(+6q^2+10q+66q+110)=0

We get rid of parentheses

6q^2+10q+66q+110=0

We add all the numbers together, and all the variables

6q^2+76q+110=0

a = 6; b = 76; c = +110;
Δ = b2-4ac
Δ = 762-4·6·110
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-56}{2*6}=\frac{-132}{12}
=-11
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+56}{2*6}=\frac{-20}{12}
=-1+2/3
$