(p2)+p=84

Solution for (p2)+p=84 equation:

(p2)+p=84

We move all terms to the left:

(p2)+p-(84)=0

We add all the numbers together, and all the variables

p^2+p-84=0

a = 1; b = 1; c = -84;
Δ = b2-4ac
Δ = 12-4·1·(-84)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{337}}{2*1}=\frac{-1-\sqrt{337}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{337}}{2*1}=\frac{-1+\sqrt{337}}{2}
$