(p-12)+(p+11)=(p+44)

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Solution for (p-12)+(p+11)=(p+44) equation: 



(p-12)+(p+11)=(p+44)

We move all terms to the left:

(p-12)+(p+11)-((p+44))=0

We get rid of parentheses

p+p-((p+44))-12+11=0



We calculate terms in parentheses: -((p+44)), so:

(p+44)

We get rid of parentheses

p+44

Back to the equation:

-(p+44)



We add all the numbers together, and all the variables

2p-(p+44)-1=0

We get rid of parentheses

2p-p-44-1=0

We add all the numbers together, and all the variables

p-45=0

We move all terms containing p to the left, all other terms to the right

p=45

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