(p-1)(p+6)=126

Solution for (p-1)(p+6)=126 equation:

(p-1)(p+6)=126

We move all terms to the left:

(p-1)(p+6)-(126)=0

We multiply parentheses ..

(+p^2+6p-1p-6)-126=0

We get rid of parentheses

p^2+6p-1p-6-126=0

We add all the numbers together, and all the variables

p^2+5p-132=0

a = 1; b = 5; c = -132;
Δ = b2-4ac
Δ = 52-4·1·(-132)
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{553}}{2*1}=\frac{-5-\sqrt{553}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{553}}{2*1}=\frac{-5+\sqrt{553}}{2}
$