(p+p+(p-6))/3=63

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Solution for (p+p+(p-6))/3=63 equation: 



(p+p+(p-6))/3=63

We move all terms to the left:

(p+p+(p-6))/3-(63)=0

We multiply all the terms by the denominator


(p+p+(p-6))-63*3=0



We calculate terms in parentheses: +(p+p+(p-6)), so:

p+p+(p-6)

We add all the numbers together, and all the variables

2p+(p-6)

We get rid of parentheses

2p+p-6

We add all the numbers together, and all the variables

3p-6

Back to the equation:

+(3p-6)



We add all the numbers together, and all the variables

(3p-6)-189=0

We get rid of parentheses

3p-6-189=0

We add all the numbers together, and all the variables

3p-195=0

We move all terms containing p to the left, all other terms to the right

3p=195

p=195/3

p=65

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