(n=8)+(n-12)

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Solution for (n=8)+(n-12) equation: 



(n=8)+(n-12)

We move all terms to the left:

(n-(8)+(n-12))=0



We calculate terms in parentheses: +(n-8+(n-12)), so:

n-8+(n-12)

determiningTheFunctionDomain
n+(n-12)-8

We get rid of parentheses

n+n-12-8

We add all the numbers together, and all the variables

2n-20

Back to the equation:

+(2n-20)



We get rid of parentheses

2n-20=0

We move all terms containing n to the left, all other terms to the right

2n=20

n=20/2

n=10

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