(n/n-3)+2=(3/2n-1)

Solution for (n/n-3)+2=(3/2n-1) equation:

(n/n-3)+2=(3/2n-1)

We move all terms to the left:

(n/n-3)+2-((3/2n-1))=0


Domain of the equation: n-3)!=0

n∈R



Domain of the equation: 2n-1))!=0

n∈R


We get rid of parentheses

n/n-((3/2n-1))-3+2=0

Fractions to decimals

-((3/2n-1))-3+2+1=0

We multiply all the terms by the denominator


-((3-3*2n-1))+2*2n-1))+1*2n-1))=0


We calculate terms in parentheses: -((3-3*2n-1)), so:

(3-3*2n-1)

We add all the numbers together, and all the variables

(-3*2n+2)

We get rid of parentheses

-3*2n+2

Wy multiply elements

-6n+2

Back to the equation:

-(-6n+2)


Wy multiply elements

-(-6n+2)+4n-1))+1*2n-1))=0

We get rid of parentheses

6n+4n-1))+1*2n-1))-2=0

We add all the numbers together, and all the variables

10n-1))+1*2n-1))-2=0