(n/2)-(1/3)=(1/6)

Solution for (n/2)-(1/3)=(1/6) equation:

(n/2)-(1/3)=(1/6)

We move all terms to the left:

(n/2)-(1/3)-((1/6))=0

We add all the numbers together, and all the variables

(+n/2)-(+1/3)-((+1/6))=0

We get rid of parentheses

n/2-1/3-((+1/6))=0

We calculate fractions


108n^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

108n^2/()+2=0

We multiply all the terms by the denominator


108n^2+2*()=0

We add all the numbers together, and all the variables

108n^2=0

a = 108; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·108·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{216}=0$