(n-7)-3(3n+10)=3n-9+2-n

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Solution for (n-7)-3(3n+10)=3n-9+2-n equation: 



(n-7)-3(3n+10)=3n-9+2-n

We move all terms to the left:

(n-7)-3(3n+10)-(3n-9+2-n)=0

We add all the numbers together, and all the variables

(n-7)-3(3n+10)-(2n-7)=0

We multiply parentheses

(n-7)-9n-(2n-7)-30=0

We get rid of parentheses

n-9n-2n-7+7-30=0

We add all the numbers together, and all the variables

-10n-30=0

We move all terms containing n to the left, all other terms to the right

-10n=30

n=30/-10

n=-3

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