(n-6)3=(n-2)/9

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Solution for (n-6)3=(n-2)/9 equation: 



(n-6)3=(n-2)/9

We move all terms to the left:

(n-6)3-((n-2)/9)=0

We multiply parentheses

3n-((n-2)/9)-18=0

We multiply all the terms by the denominator


3n*9)-((n-2)-18*9)=0

We add all the numbers together, and all the variables

3n*9)-((n-2)=0

Wy multiply elements

27n^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{54}=0$

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