(n-3)/2=(n-6)/3

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Solution for (n-3)/2=(n-6)/3 equation: 



(n-3)/2=(n-6)/3

We move all terms to the left:

(n-3)/2-((n-6)/3)=0

We calculate fractions


n/()+(-((n-6)*2)/()=0



We calculate terms in parentheses: +(-((n-6)*2)/(), so:

-((n-6)*2)/(

We multiply all the terms by the denominator


-((n-6)*2)



We calculate terms in parentheses: -((n-6)*2), so:

(n-6)*2

We multiply parentheses

2n-12

Back to the equation:

-(2n-12)



We get rid of parentheses

-2n+12

Back to the equation:

+(-2n+12)



We get rid of parentheses

n/()-2n+12=0

We multiply all the terms by the denominator


n-2n*()+12*()=0

We add all the numbers together, and all the variables

n-2n*()=0

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