(n-3)(n-4)(n-5)=120

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Solution for (n-3)(n-4)(n-5)=120 equation: 



(n-3)(n-4)(n-5)=120

We move all terms to the left:

(n-3)(n-4)(n-5)-(120)=0

We multiply parentheses ..

(+n^2-4n-3n+12)(n-5)-120=0

We move all terms containing n to the left, all other terms to the right

(+n^2-4n-3n+12)(n-5)=120

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