(n-3)(n+4)(n-1)=

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Solution for (n-3)(n+4)(n-1)= equation:


Simplifying
(n + -3)(n + 4)(n + -1) = 0

Reorder the terms:
(-3 + n)(n + 4)(n + -1) = 0

Reorder the terms:
(-3 + n)(4 + n)(n + -1) = 0

Reorder the terms:
(-3 + n)(4 + n)(-1 + n) = 0

Multiply (-3 + n) * (4 + n)
(-3(4 + n) + n(4 + n))(-1 + n) = 0
((4 * -3 + n * -3) + n(4 + n))(-1 + n) = 0
((-12 + -3n) + n(4 + n))(-1 + n) = 0
(-12 + -3n + (4 * n + n * n))(-1 + n) = 0
(-12 + -3n + (4n + n2))(-1 + n) = 0

Combine like terms: -3n + 4n = 1n
(-12 + 1n + n2)(-1 + n) = 0

Multiply (-12 + 1n + n2) * (-1 + n)
(-12(-1 + n) + 1n * (-1 + n) + n2(-1 + n)) = 0
((-1 * -12 + n * -12) + 1n * (-1 + n) + n2(-1 + n)) = 0
((12 + -12n) + 1n * (-1 + n) + n2(-1 + n)) = 0
(12 + -12n + (-1 * 1n + n * 1n) + n2(-1 + n)) = 0
(12 + -12n + (-1n + 1n2) + n2(-1 + n)) = 0
(12 + -12n + -1n + 1n2 + (-1 * n2 + n * n2)) = 0
(12 + -12n + -1n + 1n2 + (-1n2 + n3)) = 0

Combine like terms: -12n + -1n = -13n
(12 + -13n + 1n2 + -1n2 + n3) = 0

Combine like terms: 1n2 + -1n2 = 0
(12 + -13n + 0 + n3) = 0
(12 + -13n + n3) = 0

Solving
12 + -13n + n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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