(n-2)-1=2-5(n+5)

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Solution for (n-2)-1=2-5(n+5) equation: 



(n-2)-1=2-5(n+5)

We move all terms to the left:

(n-2)-1-(2-5(n+5))=0

We get rid of parentheses

n-(2-5(n+5))-2-1=0



We calculate terms in parentheses: -(2-5(n+5)), so:

2-5(n+5)

determiningTheFunctionDomain
-5(n+5)+2

We multiply parentheses

-5n-25+2

We add all the numbers together, and all the variables

-5n-23

Back to the equation:

-(-5n-23)



We add all the numbers together, and all the variables

n-(-5n-23)-3=0

We get rid of parentheses

n+5n+23-3=0

We add all the numbers together, and all the variables

6n+20=0

We move all terms containing n to the left, all other terms to the right

6n=-20

n=-20/6

n=-3+1/3

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