(n-1)=(2n+4)=0

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Solution for (n-1)=(2n+4)=0 equation: 



(n-1)=(2n+4)=0

We move all terms to the left:

(n-1)-((2n+4))=0

We get rid of parentheses

n-((2n+4))-1=0



We calculate terms in parentheses: -((2n+4)), so:

(2n+4)

We get rid of parentheses

2n+4

Back to the equation:

-(2n+4)



We get rid of parentheses

n-2n-4-1=0

We add all the numbers together, and all the variables

-1n-5=0

We move all terms containing n to the left, all other terms to the right

-n=5

n=5/-1

n=-5

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