(n+8)+(n-12)=2n+(-4)

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Solution for (n+8)+(n-12)=2n+(-4) equation: 



(n+8)+(n-12)=2n+(-4)

We move all terms to the left:

(n+8)+(n-12)-(2n+(-4))=0

We get rid of parentheses

n+n-(2n+(-4))+8-12=0



We calculate terms in parentheses: -(2n+(-4)), so:

2n+(-4)

We add all the numbers together, and all the variables

2n-4

Back to the equation:

-(2n-4)



We add all the numbers together, and all the variables

2n-(2n-4)-4=0

We get rid of parentheses

2n-2n+4-4=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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