(n+7)+(n+3)+(n+2)=40

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Solution for (n+7)+(n+3)+(n+2)=40 equation:


Simplifying
(n + 7) + (n + 3) + (n + 2) = 40

Reorder the terms:
(7 + n) + (n + 3) + (n + 2) = 40

Remove parenthesis around (7 + n)
7 + n + (n + 3) + (n + 2) = 40

Reorder the terms:
7 + n + (3 + n) + (n + 2) = 40

Remove parenthesis around (3 + n)
7 + n + 3 + n + (n + 2) = 40

Reorder the terms:
7 + n + 3 + n + (2 + n) = 40

Remove parenthesis around (2 + n)
7 + n + 3 + n + 2 + n = 40

Reorder the terms:
7 + 3 + 2 + n + n + n = 40

Combine like terms: 7 + 3 = 10
10 + 2 + n + n + n = 40

Combine like terms: 10 + 2 = 12
12 + n + n + n = 40

Combine like terms: n + n = 2n
12 + 2n + n = 40

Combine like terms: 2n + n = 3n
12 + 3n = 40

Solving
12 + 3n = 40

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 3n = 40 + -12

Combine like terms: 12 + -12 = 0
0 + 3n = 40 + -12
3n = 40 + -12

Combine like terms: 40 + -12 = 28
3n = 28

Divide each side by '3'.
n = 9.333333333

Simplifying
n = 9.333333333

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