(n+5)-(n+3)=4(n+4)

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Solution for (n+5)-(n+3)=4(n+4) equation:


Simplifying
(n + 5) + -1(n + 3) = 4(n + 4)

Reorder the terms:
(5 + n) + -1(n + 3) = 4(n + 4)

Remove parenthesis around (5 + n)
5 + n + -1(n + 3) = 4(n + 4)

Reorder the terms:
5 + n + -1(3 + n) = 4(n + 4)
5 + n + (3 * -1 + n * -1) = 4(n + 4)
5 + n + (-3 + -1n) = 4(n + 4)

Reorder the terms:
5 + -3 + n + -1n = 4(n + 4)

Combine like terms: 5 + -3 = 2
2 + n + -1n = 4(n + 4)

Combine like terms: n + -1n = 0
2 + 0 = 4(n + 4)
2 = 4(n + 4)

Reorder the terms:
2 = 4(4 + n)
2 = (4 * 4 + n * 4)
2 = (16 + 4n)

Solving
2 = 16 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
2 + -4n = 16 + 4n + -4n

Combine like terms: 4n + -4n = 0
2 + -4n = 16 + 0
2 + -4n = 16

Add '-2' to each side of the equation.
2 + -2 + -4n = 16 + -2

Combine like terms: 2 + -2 = 0
0 + -4n = 16 + -2
-4n = 16 + -2

Combine like terms: 16 + -2 = 14
-4n = 14

Divide each side by '-4'.
n = -3.5

Simplifying
n = -3.5

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