(n+5)(n-4/2)=5

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Solution for (n+5)(n-4/2)=5 equation: 


n in (-oo:+oo)

(n+5)*(n-(4/2)) = 5 // - 5

(n+5)*(n-(4/2))-5 = 0

(n+5)*(n-2)-5 = 0

(n+5)*(n-2)-5 = 0

n^2+3*n-15 = 0

n^2+3*n-15 = 0

n^2+3*n-15 = 0

DELTA = 3^2-(-15*1*4)

DELTA = 69

DELTA > 0

n = (69^(1/2)-3)/(1*2) or n = (-69^(1/2)-3)/(1*2)

n = (69^(1/2)-3)/2 or n = (-(69^(1/2)+3))/2

(n+(69^(1/2)+3)/2)*(n-((69^(1/2)-3)/2)) = 0

(n+(69^(1/2)+3)/2)*(n-((69^(1/2)-3)/2)) = 0

( n+(69^(1/2)+3)/2 )

n+(69^(1/2)+3)/2 = 0 // - (69^(1/2)+3)/2

n = -((69^(1/2)+3)/2)

( n-((69^(1/2)-3)/2) )

n-((69^(1/2)-3)/2) = 0 // + (69^(1/2)-3)/2

n = (69^(1/2)-3)/2

n in { -((69^(1/2)+3)/2), (69^(1/2)-3)/2 }

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