(n+4)2=28

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Solution for (n+4)2=28 equation: 



(n+4)2=28

We move all terms to the left:

(n+4)2-(28)=0

We multiply parentheses

2n+8-28=0

We add all the numbers together, and all the variables

2n-20=0

We move all terms containing n to the left, all other terms to the right

2n=20

n=20/2

n=10

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