(n+4)-2(n)=(n+2)-24

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Solution for (n+4)-2(n)=(n+2)-24 equation:


Simplifying
(n + 4) + -2(n) = (n + 2) + -24

Reorder the terms:
(4 + n) + -2(n) = (n + 2) + -24

Remove parenthesis around (4 + n)
4 + n + -2(n) = (n + 2) + -24

Combine like terms: n + -2n = -1n
4 + -1n = (n + 2) + -24

Reorder the terms:
4 + -1n = (2 + n) + -24

Remove parenthesis around (2 + n)
4 + -1n = 2 + n + -24

Reorder the terms:
4 + -1n = 2 + -24 + n

Combine like terms: 2 + -24 = -22
4 + -1n = -22 + n

Solving
4 + -1n = -22 + n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
4 + -1n + -1n = -22 + n + -1n

Combine like terms: -1n + -1n = -2n
4 + -2n = -22 + n + -1n

Combine like terms: n + -1n = 0
4 + -2n = -22 + 0
4 + -2n = -22

Add '-4' to each side of the equation.
4 + -4 + -2n = -22 + -4

Combine like terms: 4 + -4 = 0
0 + -2n = -22 + -4
-2n = -22 + -4

Combine like terms: -22 + -4 = -26
-2n = -26

Divide each side by '-2'.
n = 13

Simplifying
n = 13

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