(n+3+3n-5)/2=n+6

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Solution for (n+3+3n-5)/2=n+6 equation: 



(n+3+3n-5)/2=n+6

We move all terms to the left:

(n+3+3n-5)/2-(n+6)=0

We add all the numbers together, and all the variables

(4n-2)/2-(n+6)=0

We get rid of parentheses

(4n-2)/2-n-6=0

We multiply all the terms by the denominator


(4n-2)-n*2-6*2=0

We add all the numbers together, and all the variables

(4n-2)-n*2-12=0

Wy multiply elements

(4n-2)-2n-12=0

We get rid of parentheses

4n-2n-2-12=0

We add all the numbers together, and all the variables

2n-14=0

We move all terms containing n to the left, all other terms to the right

2n=14

n=14/2

n=7

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