(n+3)/(2n)=4/5

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Solution for (n+3)/(2n)=4/5 equation: 



(n+3)/(2n)=4/5

We move all terms to the left:

(n+3)/(2n)-(4/5)=0



Domain of the equation: 2n!=0

n!=0/2

n!=0

n∈R



We add all the numbers together, and all the variables

(n+3)/2n-(+4/5)=0

We get rid of parentheses

(n+3)/2n-4/5=0

We calculate fractions


(5n+15)/10n+(-8n)/10n=0

We multiply all the terms by the denominator


(5n+15)+(-8n)=0

We get rid of parentheses

5n-8n+15=0

We add all the numbers together, and all the variables

-3n+15=0

We move all terms containing n to the left, all other terms to the right

-3n=-15

n=-15/-3

n=+5

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