(n+2)+(n+1)+(2n-1)=

Solution for (n+2)+(n+1)+(2n-1)= equation:

Simplifying
(n + 2) + (n + 1) + (2n + -1) = 0

Reorder the terms:
(2 + n) + (n + 1) + (2n + -1) = 0

Remove parenthesis around (2 + n)
2 + n + (n + 1) + (2n + -1) = 0

Reorder the terms:
2 + n + (1 + n) + (2n + -1) = 0

Remove parenthesis around (1 + n)
2 + n + 1 + n + (2n + -1) = 0

Reorder the terms:
2 + n + 1 + n + (-1 + 2n) = 0

Remove parenthesis around (-1 + 2n)
2 + n + 1 + n + -1 + 2n = 0

Reorder the terms:
2 + 1 + -1 + n + n + 2n = 0

Combine like terms: 2 + 1 = 3
3 + -1 + n + n + 2n = 0

Combine like terms: 3 + -1 = 2
2 + n + n + 2n = 0

Combine like terms: n + n = 2n
2 + 2n + 2n = 0

Combine like terms: 2n + 2n = 4n
2 + 4n = 0

Solving
2 + 4n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 4n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 4n = 0 + -2
4n = 0 + -2

Combine like terms: 0 + -2 = -2
4n = -2

Divide each side by '4'.
n = -0.5

Simplifying
n = -0.5