(n+2)(n-3)=0

Solution for (n+2)(n-3)=0 equation:

Simplifying
(n + 2)(n + -3) = 0

Reorder the terms:
(2 + n)(n + -3) = 0

Reorder the terms:
(2 + n)(-3 + n) = 0

Multiply (2 + n) * (-3 + n)
(2(-3 + n) + n(-3 + n)) = 0
((-3 * 2 + n * 2) + n(-3 + n)) = 0
((-6 + 2n) + n(-3 + n)) = 0
(-6 + 2n + (-3 * n + n * n)) = 0
(-6 + 2n + (-3n + n2)) = 0

Combine like terms: 2n + -3n = -1n
(-6 + -1n + n2) = 0

Solving
-6 + -1n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(-2 + -1n)(3 + -1n) = 0

Subproblem 1
Set the factor '(-2 + -1n)' equal to zero and attempt to solve:

Simplifying
-2 + -1n = 0

Solving
-2 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1n = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1n = 0 + 2
-1n = 0 + 2

Combine like terms: 0 + 2 = 2
-1n = 2

Divide each side by '-1'.
n = -2

Simplifying
n = -2
Subproblem 2
Set the factor '(3 + -1n)' equal to zero and attempt to solve:

Simplifying
3 + -1n = 0

Solving
3 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1n = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1n = 0 + -3
-1n = 0 + -3

Combine like terms: 0 + -3 = -3
-1n = -3

Divide each side by '-1'.
n = 3

Simplifying
n = 3
Solution
n = {-2, 3}