(n+10)+(n+10)=(n-10)+(n-10)+(n-10)+(n-10)

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Solution for (n+10)+(n+10)=(n-10)+(n-10)+(n-10)+(n-10) equation: 



(n+10)+(n+10)=(n-10)+(n-10)+(n-10)+(n-10)

We move all terms to the left:

(n+10)+(n+10)-((n-10)+(n-10)+(n-10)+(n-10))=0

We get rid of parentheses

n+n-((n-10)+(n-10)+(n-10)+(n-10))+10+10=0



We calculate terms in parentheses: -((n-10)+(n-10)+(n-10)+(n-10)), so:

(n-10)+(n-10)+(n-10)+(n-10)

We get rid of parentheses

n+n+n+n-10-10-10-10

We add all the numbers together, and all the variables

4n-40

Back to the equation:

-(4n-40)



We add all the numbers together, and all the variables

2n-(4n-40)+20=0

We get rid of parentheses

2n-4n+40+20=0

We add all the numbers together, and all the variables

-2n+60=0

We move all terms containing n to the left, all other terms to the right

-2n=-60

n=-60/-2

n=+30

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