(n+1)/(3n-9)=3/2

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Solution for (n+1)/(3n-9)=3/2 equation: 


D( n )

3*n-9 = 0

3*n-9 = 0

3*n-9 = 0

3*n-9 = 0 // + 9

3*n = 9 // : 3

n = 9/3

n = 3

n in (-oo:3) U (3:+oo)

(n+1)/(3*n-9) = 3/2 // - 3/2

(n+1)/(3*n-9)-(3/2) = 0

(n+1)/(3*n-9)-3/2 = 0

(2*(n+1))/(2*(3*n-9))+(-3*(3*n-9))/(2*(3*n-9)) = 0

2*(n+1)-3*(3*n-9) = 0

29-7*n = 0

(29-7*n)/(2*(3*n-9)) = 0

(29-7*n)/(2*(3*n-9)) = 0 // * 2*(3*n-9)

29-7*n = 0

29-7*n = 0 // - 29

-7*n = -29 // : -7

n = -29/(-7)

n = 29/7

n = 29/7

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