(n+1)+(n+3)+(n+5)=141

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Solution for (n+1)+(n+3)+(n+5)=141 equation:


Simplifying
(n + 1) + (n + 3) + (n + 5) = 141

Reorder the terms:
(1 + n) + (n + 3) + (n + 5) = 141

Remove parenthesis around (1 + n)
1 + n + (n + 3) + (n + 5) = 141

Reorder the terms:
1 + n + (3 + n) + (n + 5) = 141

Remove parenthesis around (3 + n)
1 + n + 3 + n + (n + 5) = 141

Reorder the terms:
1 + n + 3 + n + (5 + n) = 141

Remove parenthesis around (5 + n)
1 + n + 3 + n + 5 + n = 141

Reorder the terms:
1 + 3 + 5 + n + n + n = 141

Combine like terms: 1 + 3 = 4
4 + 5 + n + n + n = 141

Combine like terms: 4 + 5 = 9
9 + n + n + n = 141

Combine like terms: n + n = 2n
9 + 2n + n = 141

Combine like terms: 2n + n = 3n
9 + 3n = 141

Solving
9 + 3n = 141

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 3n = 141 + -9

Combine like terms: 9 + -9 = 0
0 + 3n = 141 + -9
3n = 141 + -9

Combine like terms: 141 + -9 = 132
3n = 132

Divide each side by '3'.
n = 44

Simplifying
n = 44

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