(n+1)*(n-1)=112

Solution for (n+1)*(n-1)=112 equation:

Simplifying
(n + 1)(n + -1) = 112

Reorder the terms:
(1 + n)(n + -1) = 112

Reorder the terms:
(1 + n)(-1 + n) = 112

Multiply (1 + n) * (-1 + n)
(1(-1 + n) + n(-1 + n)) = 112
((-1 * 1 + n * 1) + n(-1 + n)) = 112
((-1 + 1n) + n(-1 + n)) = 112
(-1 + 1n + (-1 * n + n * n)) = 112
(-1 + 1n + (-1n + n2)) = 112

Combine like terms: 1n + -1n = 0
(-1 + 0 + n2) = 112
(-1 + n2) = 112

Solving
-1 + n2 = 112

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + n2 = 112 + 1

Combine like terms: -1 + 1 = 0
0 + n2 = 112 + 1
n2 = 112 + 1

Combine like terms: 112 + 1 = 113
n2 = 113

Simplifying
n2 = 113

Take the square root of each side:
n = {-10.630145813, 10.630145813}