(n+)(n+2)-n(n+5)=66

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Solution for (n+)(n+2)-n(n+5)=66 equation: 



(n+)(n+2)-n(n+5)=66

We move all terms to the left:

(n+)(n+2)-n(n+5)-(66)=0

We add all the numbers together, and all the variables

(+n)(n+2)-n(n+5)-66=0

We multiply parentheses

-n^2+(+n)(n+2)-5n-66=0

We multiply parentheses ..

-n^2+(+n^2+2n)-5n-66=0

We add all the numbers together, and all the variables

-1n^2+(+n^2+2n)-5n-66=0

We get rid of parentheses

-1n^2+n^2+2n-5n-66=0

We add all the numbers together, and all the variables

-3n-66=0

We move all terms containing n to the left, all other terms to the right

-3n=66

n=66/-3

n=-22

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