(n)/(n-4)=-(32)/(7)

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Solution for (n)/(n-4)=-(32)/(7) equation: 



(n)/(n-4)=-(32)/(7)

We move all terms to the left:

(n)/(n-4)-(-(32)/(7))=0



Domain of the equation: (n-4)!=0

We move all terms containing n to the left, all other terms to the right

n!=4

n∈R



We get rid of parentheses

n/(n-4)+32/7=0

We calculate fractions


7n/(7n-28)+(32n-128)/(7n-28)=0

We multiply all the terms by the denominator


7n+(32n-128)=0

We get rid of parentheses

7n+32n-128=0

We add all the numbers together, and all the variables

39n-128=0

We move all terms containing n to the left, all other terms to the right

39n=128

n=128/39

n=3+11/39

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