(m-4)(m-4)=0

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Solution for (m-4)(m-4)=0 equation: 



(m-4)(m-4)=0

We multiply parentheses ..

(+m^2-4m-4m+16)=0

We get rid of parentheses

m^2-4m-4m+16=0

We add all the numbers together, and all the variables

m^2-8m+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{8}{2}=4$

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