(m-2)/7=(m-4)/5

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Solution for (m-2)/7=(m-4)/5 equation:



(m-2)/7=(m-4)/5
We move all terms to the left:
(m-2)/7-((m-4)/5)=0
We calculate fractions
m/()+(-((m-4)*7)/()=0
We calculate terms in parentheses: +(-((m-4)*7)/(), so:
-((m-4)*7)/(
We multiply all the terms by the denominator
-((m-4)*7)
We calculate terms in parentheses: -((m-4)*7), so:
(m-4)*7
We multiply parentheses
7m-28
Back to the equation:
-(7m-28)
We get rid of parentheses
-7m+28
Back to the equation:
+(-7m+28)
We get rid of parentheses
m/()-7m+28=0
We multiply all the terms by the denominator
m-7m*()+28*()=0
We add all the numbers together, and all the variables
m-7m*()=0

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